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4x^2-8x-10000=0
a = 4; b = -8; c = -10000;
Δ = b2-4ac
Δ = -82-4·4·(-10000)
Δ = 160064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{160064}=\sqrt{64*2501}=\sqrt{64}*\sqrt{2501}=8\sqrt{2501}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8\sqrt{2501}}{2*4}=\frac{8-8\sqrt{2501}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8\sqrt{2501}}{2*4}=\frac{8+8\sqrt{2501}}{8} $
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